b^2=10-3b

Solution for b^2=10-3b equation:

Simplifying
b2 = 10 + -3b

Solving
b2 = 10 + -3b

Solving for variable 'b'.

Reorder the terms:
-10 + 3b + b2 = 10 + -3b + -10 + 3b

Reorder the terms:
-10 + 3b + b2 = 10 + -10 + -3b + 3b

Combine like terms: 10 + -10 = 0
-10 + 3b + b2 = 0 + -3b + 3b
-10 + 3b + b2 = -3b + 3b

Combine like terms: -3b + 3b = 0
-10 + 3b + b2 = 0

Factor a trinomial.
(-5 + -1b)(2 + -1b) = 0

Subproblem 1
Set the factor '(-5 + -1b)' equal to zero and attempt to solve:

Simplifying
-5 + -1b = 0

Solving
-5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1b = 0 + 5
-1b = 0 + 5

Combine like terms: 0 + 5 = 5
-1b = 5

Divide each side by '-1'.
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-5, 2}